-16x^2+4x+2=0

Solution for -16x^2+4x+2=0 equation:

-16x^2+4x+2=0

a = -16; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·(-16)·2
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12}{2*-16}=\frac{-16}{-32}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12}{2*-16}=\frac{8}{-32}
=-1/4
$